Question

Given three real numbers `a`, `b`, and `c`. It is known that `a+b+c>0`, `ab+bc+ca>0`, and `abc>0`. Prove that `a>0`, `b>0`, and `c>0`.

Difficulty level (1 very easy - 10 very hard): 4

Topics:
Algebra -> Inequalities Proof and Example -> Proof by Contradiction
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