Question

Given natural numbers n, a, b such that `3n+1=a^2` and `4n+1=b^2`, prove that:

a. n is divisible by 8 (easier)

b. n is divisible by 56

Difficulty level (1 very easy - 10 very hard): 9

Number Theory -> Modular Arithmetic / Remainder Arithmetic -> Divisibility Rules Algebra -> Equations -> Diophantine Equations

Sources:

There are no comments yet.

You must log in to post a comment.