Question

In the plane, a square and a point `P` are given. Prove that it is impossible for the distances from `P` to the vertices of the square to be `1`, `1`, `2`, and `3` centimeters?

Difficulty level (1 very easy - 10 very hard): 4

Topics:
Geometry -> Plane Geometry -> Triangles Proof and Example -> Proof by Contradiction Geometry -> Plane Geometry -> Triangle Inequality
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